This is a straightforward application of Friedel-Crafts Reaction. A hydrogen on the ring is replaced by a group like methyl or ethyl and so on. Be sure to show formal charges, if applicable. The Friedel-Crafts alkylation involves the electrophilic substitution of alkyl groups on aromatic rings when arenes are treated with alkyl halides in presence of Lewis acids. AIPMT 2009: Benzene reacts with CH3Cl in the presence of anhy. Knowing the mechanism of electrophilic aromatic subsitution and the effect on this reaction of substitutents in the ring, we can explain some of the reactions we have already seen. The electrophilic substitution reaction between benzene and chloromethane. Chlorobenzene on reaction with CH3Cl in the presence of anhy. Since methyl group activates the ring, making the ring more reactive, the temperature has to be lowered to 30 ºC to prevent multiple substitutions Reaction of alkylbenzene – nitration . AlCl3 to form (A) toluene (B) chlorobenzene (C) benzylchloride (D) xylene. AlCl3 will give * This reaction is catalyzed by Lewis acids like anhydrous AlCl 3, FeX 3, ZnCl 2, BF 3 etc. * The alkenes or alcohols can also be used to alkylate aromatic rings under Friedel-Crafts conditions. Discover Your Movement Family Services; Professional Services; Events; Store; Blog CH3Cl in the presence of anhydrous AlCl3 acts as alkylation agent and introduces an alkyl group.This reaction is known as Friedel-Craft s alkylation of benzene. Chlorobenzene on reaction with CH3Cl in the presence of AlCl3 will give. Check Answer Click hereto get an answer to your question ️ Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: Friedel Crafts alkylation CH3Cl + AlCl3 CH3 this is more reactive than the starting material, benzene CH3Cl + AlCl3 CH3 CH3 CH3 CH3 CH3 etc. CH3Cl + AlCl3 → CH3+ + AlCl4- C6H5H + CH3+ + AlCl4- → C6H5CH3 + HCl + AlCl3’ This reaction is known as the Friedel-Crafts Reaction. Alkylation means substituting an alkyl group into something - in this case into a benzene ring. C6H5CH3 + Cl2 → C6H4(CH3Cl) + HCl; Further substitutions are possible, producing (dichloromethyl)benzene and (trichloromethyl)benzene. Draw the structure of the product in the following reaction of aniline with CH3Cl in the presence of AlCl3. asked May 23, 2019 in Chemistry by Jagan (21.1k points) chloro benzene; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries.